Answer
$a_1=A$
$a_2=A+d$
$a_3=A+2d$
$a_4=A+3d$
$a_5=A+4d$
Work Step by Step
If $a_n=a_{n-1}+d$ and $a_1=A$, then
$a_2=a_{1}+d=A+d$
$a_3=a_{2}+d=(A+d)+d=A+2d$
$a_4=a_{3}+d=(A+2d)+d=A+3d$
$a_5=a_{4}+d=(A+3d)+d=A+4d$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 45
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