Answer
$\dfrac{1}{2},1,\dfrac{9}{8},1,\dfrac{25}{32}$
Work Step by Step
We are given the sequence:
$\{c_n\}=\left\{\dfrac{n^2}{2^n}\right\}$
Determine the first 5 terms of the sequence by substituting 1, 2, 3, 4, 5 for $n$:
$a_1=\dfrac{1^2}{2^1}=\dfrac{1}{2}$
$a_2=\dfrac{2^2}{2^2}=1$
$a_3=\dfrac{3^2}{2^3}=\dfrac{9}{8}$
$a_4=\dfrac{4^2}{2^4}=1$
$a_5=\dfrac{5^2}{2^5}=\dfrac{25}{32}$
