Answer
$\ln{2}-\ln{3}+...+(-1)^n\ln{n}$
Work Step by Step
$\sum_{k=2}^{n} ((-1)^k\ln{k})=((-1)^2\ln{2})+((-1)^3\ln{3})+...+((-1)^n\ln{n})=\ln{2}-\ln{3}+...+(-1)^n\ln{n}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 57
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