Answer
$a_1=1,a_2=2$
$a_3=2$
$a_4=4$
$a_5=8$
Work Step by Step
If $a_n=(a_{n-1})(a_{n-2})$ and $a_1=1,a_2=2$, then
$a_3=(a_{2})(a_{1})=(2)(1)=2$
$a_4=(a_{3})(a_{2})=(2)(2)=4$
$a_5=(a_{4})(a_{3})=(4)(2)=8$
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