Answer
$=\frac{1}{2}+\frac{4}{2}+...+ \frac{n^2}{2}$
Work Step by Step
$\sum_{k=1}^{n} \frac{k^2}{2}=\frac{1^2}{2}+\frac{2^2}{2}+...+ \frac{n^2}{2}=\frac{1}{2}+\frac{4}{2}+...+ \frac{n^2}{2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 51
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