Answer
$362,880$
Work Step by Step
We know that $n!=n\cdot(n-1)\cdot (n-2)...\cdot 3\cdot2\cdot1.$
Hence,
$9!=9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=362,880$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 807: 10
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