Answer
16
Work Step by Step
Integrate with respect to x by taking the antiderivative of each term. Then plug in limits to evaluate:
$=\frac{3x^3}{3}-\frac{4x^2}{2}+7x=x^3-2x^2+7x$ with limits from -1 to 1
$=[(1)^3-2(1)^2+7(1)]-[(-1)^3-2(-1)^2+7(-1)]$
$=(1-2+7)-(-1-2-7)=6-(-10)=16$
