Answer
$y'=(1+sinx)\times cos(x-cosx)$
Work Step by Step
First, find the derivative of y and u. Don't forget to apply chain rule for y':
$y'=cosu \times u'$
$u'=1+sinx$
Then plug in u and u' into y':
$y'=(1+sinx)\times cos(x-cosx)$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
