Answer
$y'=6(x^2-5x)^5-2(x^2-5x)^6(2x-5)^{-2}$
Work Step by Step
Take the derivative of y and apply chain rule:
$y'=(2x-5)^{-1}\times6(x^2-5x)^5\times(2x-5)+(x^2-5x)^6\times-1(2x-5)^{-2}\times2=6(x^2-5x)^5-2(x^2-5x)^6(2x-5)^{-2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 30
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