Answer
$3\tan^{2}x\sec^{2}x$
Work Step by Step
Let $y= u^{3}$ and $u=\tan x$
Then, according to the chain rule,
$\frac{dy}{dx}=\frac{dy}{du}\times\frac{du}{dx}= 3u^{2}\times\sec^{2}x= 3\tan^{2}x\sec^{2}x$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 17
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