Answer
$y'=1/2\sqrt cosx$
Work Step by Step
First, find the derivative of y and u. Don't forget to apply chain rule for y':
$y'=1/2(u)^{-1/2}\times u'$
$u'=cosx$
Then plug in u and u' into y':
$y'=1/2(cosx)^{-1/2}\times cosx=1/2\sqrt cosx$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 5
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