Answer
$s'=\frac{12}{3π}cos(3t)-\frac{4}{π}sin(5t)$
Work Step by Step
Take the derivative and apply chain rule:
$s'=\frac{4}{3π}cos(3t)\times3-\frac{4}{5π}sin(5t)\times5=\frac{12}{3π}cos(3t)-\frac{4}{π}sin(5t)$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 21
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