Answer
$$ -\frac{1}{3}\cot ^{3} x-\frac{1}{5}\cot ^{5} x+c$$
Work Step by Step
\begin{align*}
\int \cot ^{2} x \csc ^{4} x d x&=\int \cot ^{2} x \csc ^{2} x \csc ^{2} xd x\\
&=\int \cot ^{2} x(1+\cot ^{2} x ) \csc ^{2} xd x\\
&=\int( \cot ^{2} x+\cot ^{4} x ) \csc ^{2} xd x\\
&= -\frac{1}{3}\cot ^{3} x-\frac{1}{5}\cot ^{5} x+c
\end{align*}