Answer
$\frac{1}{8}(4\ln x+5)^2+c.$
Work Step by Step
Let $ u=4\ln x+5$, then $ du= \frac{4}{x} dx $ and hence
$$\int \frac{4\ln x +5}{x}dx = \frac{1}{4}\int udu=\frac{1}{8}u^2+c\\
=\frac{1}{8}(4\ln x+5)^2+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 96
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