Answer
$$ y'= 2x+14.$$
Work Step by Step
Taking the $\ln $ on both sides of the equation, we get
$$\ln y= \ln (x+5)(x+9)$$
Then using the properties of $\ln $, we can write
$$\ln y= \ln (x+5)+\ln(x+9).$$
Now taking the derivative for the above equation, we have
$$\frac{y'}{y}= \frac{1}{x+5}+ \frac{1}{x+9},$$
Hence $ y'$ is given by
$$ y'=y\left( \frac{1}{x+5}+ \frac{1}{x+9}\right)=(x+5)(x+9)\left( \frac{1}{x+5}+ \frac{1}{x+9}\right)\\
x+9+x+5=2x+14.$$
