Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 106

Answer

$\ln 2$

Work Step by Step

Using the fact that $\frac{u'}{u}=\ln u $, we have $$\int_1^2 \frac{1}{x}dx =\ln x|_1^2=\ln 2-\ln 1=\ln 2 $$ where used the property $\ln 1=0.$
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