Answer
$$ \frac{3^{\sin x}}{\ln 3} +c. $$
Work Step by Step
Let $ u= 3^{\sin x}$, then $ du=\ln 3 \cos x 3^{\sin x} dx $ and hence
$$\int \cos x 3^{\sin x}dx =\frac{1}{\ln 3} \int du +c= \frac{3^{\sin x}}{\ln 3} +c. $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 104
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