Answer
$$-48$$
Work Step by Step
Given $$\lim _{(x, y) \rightarrow(-3,-2)}\left(x^{2} y^{3}+4 x y\right)$$
Since $ \left(x^{2} y^{3}+4 x y\right)$, then by substitution, we get
\begin{align*}
\lim _{(x, y) \rightarrow(-3,-2)}\left(x^{2} y^{3}+4 x y\right)&=\lim _{(x, y) \rightarrow(-3,-2)}\left((-3)^{2} (-2)^{3}+4 (-3)(-2)\right)\\
&= -48
\end{align*}