Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.2 Limits and Continuity in Several Variables - Exercises - Page 772: 30

Answer

$$0$$

Work Step by Step

Given $$\lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}+y^{2}}{1+y^{2}}$$ Since $ \dfrac{x^{2}+y^{2}}{1+y^{2}}$ is continuous at $(0,0)$, then by substitution, we get \begin{align*} \lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}+y^{2}}{1+y^{2}}&=\lim _{(x, y) \rightarrow(0,0)} \frac{0}{1+0}\\ &=0 \end{align*}
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