Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.2 Limits and Continuity in Several Variables - Exercises - Page 772: 17

Answer

See the proof below.

Work Step by Step

Along the $ x $-axis $ y=0$, we have $$ \lim\limits_{(x,y) \to (0,0)}\frac{x}{x^2+ y^2 } = \lim\limits_{(x,y) \to (0,0)}\frac{x}{x^2 }= \lim\limits_{(x,y) \to (0,0)}\frac{1}{x }=\infty.$$ hence the limit does not exist.
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