Answer
$$1$$
Work Step by Step
$$(i+j)\cdot (j+k)=i\cdot j+i\cdot k+j\cdot j+j\cdot k\\
=0+0+1+0=1.$$
Note that the product of $i\cdot j=i\cdot k=j\cdot k=0$, because they are perpendicular ($\theta=90^{\circ}$).
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