Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 21

Answer

$$\theta=\cos^{-1}\frac{1}{\sqrt{10}}.$$

Work Step by Step

\begin{align*} \cos \theta &=\frac{\langle 1,1,0\rangle \cdot \langle 0,1,2\rangle}{\|\langle 1,1,0\rangle\|\|\langle 0,1,2\rangle\|}\\ &=\frac{0+1+0}{\sqrt{1+1+0}\sqrt{0+1+4}}\\ &=\frac{1}{\sqrt{2}\sqrt{5}}\\ &=\frac{1}{\sqrt{10}} \end{align*} That is $$\theta=\cos^{-1}\frac{1}{\sqrt{10}}.$$
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