Answer
0
Work Step by Step
$\textbf{k}\cdot\textbf{j}=kj \cos \theta= 1\times1\times\cos 90^{\circ}= 0$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 7
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