Answer
5
Work Step by Step
We know that, In general $(a_{1}\hat{i}+b_{1}\hat{j})\cdot(a_{2}\hat{i}+b_{2}\hat{j})= a_{1}a_{2}+b_{1}b_{2}$.
Then, $<3,1>\cdot<4,-7>= 3\times4+(1\times-7)= 5$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 5
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