Answer
12
Work Step by Step
Recall that
$(a_{1}\hat{i}+a_{2}\hat{j}+a_{3}\hat{k})\cdot (b_{1}\hat{i}+b_{2}\hat{j}+ b_{3}\hat{k})=$$a_{1}b_{1}+a_{2}b_{2}+a_{3}b_{3}$.
Then,
$<1,1,1>\cdot<6,4,2>= 1\times6+1\times4+1\times2= 12$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 666: 4
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
