Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 326: 98

Answer

(a) 20ºC; The temperature of the surroundings (b) At T=160ºC

Work Step by Step

(a) We can see that the graph of time vs temperature is asymptotic to the line T = 20ºC. As the time increases, the temperature of the object gets more and more closer to 20ºC which therefore is its limit as ${h \to \infty}$. This is the temperature of the surroundings because temperature of any object approaches the temperature of its surroundings following $Newton's$ $law$ $of$ $cooling.$ (b) According to $Newton's$ $law$ $of$ $cooling$, the rate of change of temperature of an object is directly proportional to the difference between its temperature and the temperature of its surroundings. This difference is maximum when T=160ºC. It can also be seen from the graph that the slope of the curve -and hence the rate of change of temperature- is greatest at this point
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