Answer
$y’=(-5-\frac{1}{x})y$
Work Step by Step
$lnxy+5x=30$
$\frac{y+xy’}{xy}+5=0$
$\frac{y}{xy}+\frac{xy’}{xy}=-5$
$\frac{1}{x}+\frac{y’}{y}=-5$
$\frac{y’}{y}=-5-\frac{1}{x}$
$y’=(-5-\frac{1}{x})y$
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