Answer
$y’=-\frac{2xy}{2y^2-3}$
Work Step by Step
$x^2-3lny+y^2=10$
$2x-\frac{3}{y}y’+2yy’=0$
$2xy-3y’+2y^2y’=0$
$y’(2y^2-3)=-2xy$
$y’=-\frac{2xy}{2y^2-3}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 326: 73
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
