Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Section 3.1 - Derivatives of Polynomials and Exponential Functions - 3.1 Exercises - Page 182: 54

Answer

a) $v=4t^3-6t^2+2t-1$ $a=12t^2-12t+2$ b) $a(1)=2$ c) See image

Work Step by Step

a) $v=\frac{d}{dt}(t^4-2t^3+t^2-t)=4t^3-6t^2+2t-1$ $a=\frac{d}{dt}(4t^3-6t^2+2t-1)=12t^2-12t+2$ b) $a(1)=12(1)^2-12(1)+2=2$ c) See image
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