Answer
a) $v=3t^2-3$, $a=6t$
b) $a(2)=12$
c) $a(-1)=-6$, $a(1)=6$
Work Step by Step
a) $v=\frac{d}{dt}(t^3-3t)=3t^2-3$
$a=\frac{d}{dt}(3t^2-3)=6t$
b) $a(2)=6\times2=12$
c) $v(t)=0$, $t=-1$ and $t=1$
$a(-1)=-1\times 6=-6$
$a(1)=1\times 6=6$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Section 3.1 - Derivatives of Polynomials and Exponential Functions - 3.1 Exercises - Page 182: 53
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