Answer
- First derivative: $$f'(x)=0.005x^4-0.06x^2$$
- Second derivative: $$f''(x)=0.02x^3-0.12x$$
Work Step by Step
$$f(x)=0.001x^5-0.02x^3$$
- First derivative: $$f'(x)=0.001\frac{d}{dx}(x^5)-0.02\frac{d}{dx}(x^3)$$
$$f'(x)=0.001\times5x^4-0.02\times3x^2$$
$$f'(x)=0.005x^4-0.06x^2$$
- Second derivative: $$f''(x)=0.005\frac{d}{dx}(x^4)-0.06\frac{d}{dx}(x^2)$$
$$f''(x)=0.005\times4x^3-0.06\times2x$$
$$f''(x)=0.02x^3-0.12x$$
