Answer
$0,-2,5$
Work Step by Step
Given: $3x^3-9x^2-30x=0$
or, $3x(x^2-3x-10)=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$3x(x^2+2x-5x-10)=0$
or, $3x(x+2)(x-5)=0$
Set each factor equal to zero, we get
$3x=0 \implies x=0$
Now, $x+2=0$, and $x-5=0$
Thus, $x=0,-2,5$
