Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 19

Answer

$\dfrac{5}{3}$

Work Step by Step

Given: $9x^2=30x-25$ or, $9x^2-30x+25=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $9x^2-15x-15x+25=0$ or, $(3x-5)(3x-5)=0$ or, $(3x-5)^2=0$ Now $3x-5=0$ This implies $x=\dfrac{5}{3}$
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