Answer
$0,-4,4$
Work Step by Step
Given: $3x^4-48x^2=0$
or, $3x^2(x^2-16)=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$3x^2(x^2-4^2)=0$
or, $3x^2(x-4)(x+4)=0 $
Set each factor equal to zero, we get
$x=0,-4,4$