Answer
$-3,\dfrac{-5}{2}$
Work Step by Step
Given: $2x(x+3)=-5x-15$
or, $2x^2+11x+15=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$2x^2+6x+5x+15=0$
or, $(x+3)(2x+5)=0 $
Now, $x+3=0$ and $2x+5=0$
This implies $x=-3,\dfrac{-5}{2}$
