Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 30

Answer

$\{ -5,4\}$.

Work Step by Step

The given equation is $x(x+9)=4(2x+5)$ Subtract $4(2x+5)$ from both sides. $x(x+9)-4(2x+5)=4(2x+5)-4(2x+5)$ Simplify. $x(x+9)-4(2x+5)=0$ Use the distributive property. $x^2+9x-8x-20=0$ Add like terms. $x^2+x-20=0$ Rewrite the middle term $x$ as $5x-4x$. $x^2+5x-4x-20=0$ Group terms. $(x^2+5x)+(-4x-20)=0$ Factor each term. $x(x+5)-4(x+5)=0$ Factor out $(x+5)$. $(x+5)(x-4)=0$ Set each factor equal to zero. $x+5=0$ or $x-4=0$ Isolate $x$. $x=-5$ or $x=4$ Check the solution. Substitute $x=-5$ into the equation. $(-5)(-5+9)=4(2(-5)+5)$ Solve both sides. $(-5)(4)=4(-10+5)$ $-20=4(-5)$ $-20=-20$ True. Check the solution. Substitute $x=4$ into the equation. $(4)(4+9)=4(2(4)+5)$ Solve both sides. $(4)(13)=4(8+5)$ $52=4(13)$ $52=52$ True. Hence, the solution set is $\{ -5,4\}$.
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