Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 29

Answer

$4$

Work Step by Step

Given: $x(x+8)=16(x-1)$ or, $x^2-8x+16=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $x^2-4x-4x+16=0$ or, $(x-4)(x-4)=0 \implies (x-4)^2=0$ Now, $x-4-0$ This implies $x=4$
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