Answer
$-4,4,-2$
Work Step by Step
Given: $x^3+2x^2=16x-32$ or, $x^3+2x^2-16x+32=0$
or, $x^2(x+2)-16(x+2)=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$(x^2-16)(x+2)=0$
or, $(x-4)(x+4)(x+2)=0 $
Set each factor equal to zero, we get
$x=-4,4,-2$
