Answer
$-1,1,2$
Work Step by Step
Given: $x^3-2x^2-x+2=0$
or, $x^2(x-2)-1(x-2)=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$(x^2-1)(x-2)=0$
or, $(x-1)(x+1)(x-2)=0 $
Set each factor equal to zero, we get
$x=-1,1,2$
