Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 20

Answer

$\dfrac{3}{2}$

Work Step by Step

Given: $4x^2=12x-9$ or, $4x^2-12x+9=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $4x^2-6x-6x+9=0$ or, $(2x-3)(2x-3)=0$ or, $(2x-3)^2=0$ Now $2x-3=0$ This implies $x=\dfrac{3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.