Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 18

Answer

$6$

Work Step by Step

Given: $x^2=12x-36$ or, $x^2-12x+36=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $x^2-6x-6x+36=0$ or, $(x-6)(x-6)=0$ or, $(x-6)^2=0$ Now $x-6=0$ This implies $x=6$
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