Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 390: 27

$-3,-2$

Given: $(x-3)(x+8)=-30$ or, $x^2+5x+6=0=0$ Need to use factorization to solve the quadratic equation. This can be factorized as follows: $x^2+2x+3x+6=0$ or, $(x+3)(x+2)=0$ Now, $x+3=0$ and $x+2=0$ This implies $x=-3,-2$