Answer
$-3,-6$
Work Step by Step
Given: $\dfrac{x^2}{18}+\dfrac{x}{2}+1=\dfrac{0}{18}$
or, $x^2+9x+18=0$
Need to use factorization to solve the quadratic equation.
This can be factorized as follows:
$x^2+3x+6x+18=0$
or, $(x+3)(x+6)=0 $
Now, $x+3=0$ and $x+6=0$
This implies $x=-3,-6$
