Answer
$0$
Work Step by Step
Since, we have from the graph:
$\sum_{i=1}^{5}a_i^2-\sum_{i=1}^{5}b_i^2=[(-4)^2+(-2)^2+0+(2)^2+(4)^2]-[(4)^2+(2)^2+0+(-2)^2+(-4)^2]$
or, $=40-40$
or, $=0$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 56
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