Answer
$\frac{3}{8}$
Work Step by Step
$\sum\limits_{i=0}^4\frac{(-1)^i}{i!}=\frac{(-1)^0}{0!}+\frac{(-1)^1}{1!}+\frac{(-1)^2}{2!}+\frac{(-1)^3}{3!}+\frac{(-1)^4}{4!}=\frac{1}{1}+\frac{-1}{1}+\frac{1}{2}+\frac{-1}{6}+\frac{1}{24}=1+(-1)+\frac{1}{2}+\frac{-1}{6}+\frac{1}{24}=\frac{12}{24}+\frac{-4}{24}+\frac{1}{24}=\frac{9}{24}=\frac{3}{8}$
