Answer
$110$
Work Step by Step
Since, we have $\sum_{i=1}^{5}[\dfrac{(i+2)!}{i!}]=\dfrac{3!}{1!}+\dfrac{4!}{2!}+\dfrac{5!}{3!}+\dfrac{6!}{4!}+\dfrac{7!}{5!}$
$=6+12+20+30+42$
Hence, we get
or, $=110$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 30
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