Answer
$\sum_{i=1}^{16}(\dfrac{i}{i+2})$
Work Step by Step
Since, we have $\dfrac{1}{3}+\dfrac{2}{4}+\dfrac{3}{5}+.......+\dfrac{16}{18}$
This can be summed up with the summation notation as:
$\sum_{i=1}^{16}(\dfrac{i}{i+2})$
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