Answer
$\sum_{i=1}^{14}(\dfrac{i}{i+1})$
Work Step by Step
Since, we have $\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+.......+\dfrac{14}{15}$
This can be summed up with the summation notation as:
$\sum_{i=1}^{14}(\dfrac{i}{i+1})$
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