Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 52

Answer

$0$

Work Step by Step

Since, we have from the graph: $\sum_{i=1}^{5}(a_i+3b_i)=[(-4)+3(4)]+[(-2)+3(2)]+[(0)+3(0)]+[(2)+3(-2)]+[(4)+3(-4)]$ or, $=8+4+0-4-8$ or, $=0$
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