Answer
$0$
Work Step by Step
Since, we have from the graph:
$\sum_{i=1}^{5}(a_i+3b_i)=[(-4)+3(4)]+[(-2)+3(2)]+[(0)+3(0)]+[(2)+3(-2)]+[(4)+3(-4)]$
or, $=8+4+0-4-8$
or, $=0$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.