Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 46

Answer

$\sum_{i=1}^{15}(ar^{i-1})$

Work Step by Step

Since, we have $a+ar+ar^2+.....ar^{14}$ This form a geometric progression sequence whose first term is $a$ with common ratio of $r$. For a geometric progression sequence, we have $s_n=ar^{(n-1)}$ Last term becomes $ar^{(n-1)}=ar^{14}$ or, $n=15$ Hence, $a+ar+ar^2+.....ar^{14}$ can be summed up with the summation notation as: $\sum_{i=1}^{15}(ar^{i-1})$
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